Find value of sin15°

Prove that sin15°=[(√3-1)/2√2]

Find value of sin15° 

solution:-we have 

  sin15°= sin(45°- 30°)

           = sin45°× cos30°- cos45°× sin30°

           =(1/√2)×(√3/2)-(1/√2)×(1/2)

          =(√3-1)/2√2 ans.