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given ∠A=∠P ,∠B=∠Q ,∠C=∠R
we have to prove that △ABC~
Both triangle have in Three condition
condition-1, AB=PQ
condition-2, AB>PQ
condition-3, AB<PQ
condition-1, AB=PQ..............(i)
given ∠A=∠P ............(ii)
∠B=∠Q.............(iii)
Now From congurent A-S-A ,
△ABC ≅△PQR
then AB=PQ
BC=QR
AC=PR
also write this (AB/PQ)= (BC/QR)=(AC/PR)=1
and given ∠A=∠P ,∠B=∠Q ,∠C=∠R
hence, △ABC~
condition-2, AB>PQ