Two water taps together can fill a tank in 75/8 hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.

let be The tap of the smaller diameter fill a tank = x hours

                  The tap of larger diameter fill a tank= x-10 hours

in,75/8 hours  Two water taps together  fill =T(tank)

in,1 hours  Two water taps together  fill=8T(tank)/75

now, in  x hours smaller diameter fill a tank=T(tank)

          in 1 hours smaller diameter fill a tank=T(tank)/x

in x-10 hours  larger diameter fill a tank=T(tank)

 in 1 hours  larger diameter fill a tank=T(tank)/( x-10)

According to question,

in,1 hours  Two water taps together  fill= in 1 hours  larger diameter fill a tank +in 1 hours  larger diameter fill a tank

T(tank)/(x) +T(tank)/( x-10)=8T(tank)/75

1/x +1/( x-10)=8/75

The tap of the smaller diameter fill a tank = 25hours

    The tap of larger diameter fill a tank= 15 hours

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