Find the value of sin(590°)

Er Chandra Bhushan
0

sin(590°)=sin(3π+50°)

1π=180°

2π=360°

3π=540°

since sin(590°) is sin(3π+50°) .(3π+50°) is in 3rd Quadrante and sin in 3rd quadrante is negative.show in below figure .In 1st Quadrante all trigonometry ratio is positive and in 2nd Quadrante only sin𝛉,cosec𝛉 Positive.In 3rd Quadrante only tan𝛉,cot𝛉 positive and forth Quadrante cos𝛉,sec𝛉 positive.

so ,sin(3π+50°) =-sin(50°)=-0.4924038765

 


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