Find the first 10 terms of the sequence an 4n+3

 Solution:-Given that an=4n+3

According to Question first 10 term 

n=1, 2,3,4,5,6,7,8,9,10

For n=1, 

a1=4×1+3=7

For n=2, 

a2=4×2+3=11

For n=3, 

a3=4×3+3=15

For n=4, 

a4=4×4+3=19

For n=5, 

a5=4×5+3=23

For n=6, 

a6=4×6+3=27

For n=7, 

a7=4×7+3=31

For n=8, 

a9=4×9+3=39

For n=10, 

a10=4×10+3=43

Hence the 10 term of the sequence 7,11,15,19,21,23,27,31,35,39,43 Ans.