solution:-let f(x) = Kx^2-3x+k and g(x)==x-1
given that g(x) is factor of f(x).
so, g(x) = 0
x-1= 0
x=1
at x=1
⇒f(1)=0(why)
⇒K1^2-3x1+k=0
⇒ k-3+K=0
⇒ 2xk=3
⇒ k=3/2
find value of k if x=2 y=1 is a solution of the equation 2x+3y=k
2x+3y=k
x=2 y=1
⇒ 4+3=k
⇒ 7=k
k=7