for what value of alpha the system of equations qquad alphax+3y=alpha-3 12x+alpha y=alpha
Solution
αx+3y=α−3 ........(i)
12x+αy=α ..........(ii)
according to Question given no solution
so use condition
a1/a2 = b1/b2 ≠ c1/c2
α/12 =3/α ≠ α−3/α\
α^2=36
α=+6,-6
(+6 is not support because put in above condition all are equal means for value of α= +6 put in condition
a1/a2 = b1/b2 ≠c1/c2 not satified)
so,α=-6 Ans