Ncert class 11 th Exercise 3.1math solution
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Ncert class 11 th Exercise 3.1math solution

 Exercise 3.1 Class 11 Maths Solutions State Board

NCERT Solutions for Class 11 Maths Chapter 3-Trigonometric Functions Exercise 3.1


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Trigonometry class 11th Math Exercise-3.1 solution

Find the radian measures corresponding to the following  degree measures.

(i) 25° (ii)-47°30' (iii)240° (iv)520°

Solution:-
(i) 25°


 The radian measures= π/180° x Degree Measures

                  =π/180° x25°

                 = 25°π/180°

               =5π/36 Answer...

(ii)-47°30'

The radian measures= π/180° x Degree Measures

                                   =π/180°x-47°+(30'/60')

                                   = π/180°x(-47°+(1/2)°)

                                  =  π/180°x(-95/2)°

                                 =-18π/72 Answe...


(iii)240°                             

The radian measures= π/180° x Degree Measures

                                   =π/180°x240°

                                  = 240°π/180°

                                 =4π/3 Answe...


(iv)520°

The radian measures= π/180°xDegree Measures

                                   =π/180°x520°

                                  = 520° π/180°

                                 =26π/9 Answe...

2.Find the degree measures corresponding to the following radian measures(use π=22/7)

(i)11/16 (ii)-4 (iii) 5π (iv) 7π/6

Solution:-
(i)11/16


 The degree measures= (180°/π)x redian Measures

                                  = (180°/π)x11/16

                                    = ((180°x7)/22)x11/16

                                   = (180°x7x11)/(22x16)

                                  = 90°x7/16

                                  =45°x7/8

                                  =315°/8

                                  =39.375°

                                  =39°+375°x60'/1000

                                = 39°22.5'

                                =39°22'+5'x60''x/10

                                 =39°22'30'' 

(ii)-4

 The degree measures= (180°/π)x redian Measures

                                  = (180°/π)x-4

                                    = (180°x7/22)x-4

                                   =-5,040/22

                                =229.09°

                              = -229°+09x60'/1000

                             = -229°5'+4x60''/10

                            = -229°5'24''

 (iii) 5π/3

The degree measures= (180°/π)x redian Measures

                                  = (180°/π)x5π /3

                                  = (180°x5/3

                                 =900°/3

                                =300° 

(iv) 7π/6

The degree measures= (180°/π)x redian Measures

                                  = (180°/π)x7π/6

                                  =210°

 3.A wheel makes 360 revolutions in one minute.Through how many radians does in turn one second.

solution:-

given that in one minute means 60 second makes 360 revolutions

so in one second makes 360/60=6 revolutions

∴ one revolution=2π

∵6 revolutions=12π Ans...

4.Find the degree measure of the angle subtended at the centre of a circle of radius 100 cm by an arc of length 22 cm.(use π=22/7)

solution:-

Given that radius of circle=100 cm 

  and arc of length=22 cm 

now The angle=arc of length/ radius of circle

    angle= (22/100)

angle in degree=(22/100)x(180°/π)

angle in degree=(22/100)x(180°/22/7)

angle in degree=(22/100)x(180°x7/22)

angle in degree=(1260°/100)

angle in degree=12.6°

angle in degree=12°+(6°x60')/10

angle in degree=12°36' Ans..

5.In a circle of diameter 40 cm,the length of a chord is 20 cm.Find the length of minor arc of the chord. 

solution:- Given that diameter of circle=40 cm 

then radius of the circle=40/2=20 cm 

     And the length of chord of the circle= 20 cm 

In a circle Chord and radius made Equilateral triangle so Each angle of Equilateral triangle=60°

angle formed between two radius and minor arc=60°=60°xπ/180°=π/3

 The length of minor Arc=radius of the circlex angle formed between radius and minor arc  

                                    = 20 cm  x π/3

                                    =20π/3

6.If two circles,arcs of the same length subtend angles 60° and 75° at the centre,find the ratio of their radii. 

Solution:- Given that  two circles 

Subtend Angle of First circle=60° =π/3

Subtend Angle of First circle= 75°=75°xπ/180°=5π/12

we know that ፀ=l/r 

so  ፀ1=l/r1 

  r1=l/ፀ1

     ፀ2=l/r2

 r2 = l/ፀ2

 According to Question,

  r1/r2 = l/ፀ1 / l/ፀ2

  r1/r2 =2/ፀ1

r1/r2 =5π/12/π/3

r1/r2 =15/12=5/4

the ratio of their radii=5:4 Ans...

 7.Find the angle in radian through which a pendulum swings if its length is 75 cm and the tip describes an arc of length.

(i) 10 cm (ii) 15 cm (iii) 21 cm

solution:-

(i) arc of length =10 cm 

l= 10 cm

A pendulum swings if its length is 75 cm Means Radius of circle=75 cm

r = 75 cm

the angle in radian=l/r

                               =10 / 75

                               = 2/15 Ans...


(ii) arc of length =10 cm 

l= 15 cm

A pendulum swings if its length is 75 cm Means Radius of circle=75 cm

r = 75 cm

the angle in radian=l/r

                               =15 / 75

                               = 1/5 Ans...

(iii) arc of length = 21 cm

l= 21 cm

A pendulum swings if its length is 75 cm Means Radius of circle=75 cm

r = 75 cm

the angle in radian=l/r

                               =21/75

                               = 7/25 Ans...

Exercise 3.2 comming soon

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