Prove that √2 is an irrational number
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Prove that √2 is an irrational number

 Prove that root two is an irrational number

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Proof:-let √2 is a rational number

Then √2=p/q

(where p and q have not a common factor and q is not equal to zero) 

Squaring both side LHS and RHS 

(√2)^2=(p/q)^2

2=p^2/q^2

2q^2=p^2

p^2=2q^2

2 divide p^2

then 2 divide p

Now again let p=2k

Square each side LHS and RHS 

p^2=4k^2 ....... 2

From 1 and 2 

2q^2=4k^2

q^2=2k^2

2 divide q^2

Then 2 divide q

Since 2 divide both p and q means p and q have a common factor but we believe that p and q have not common factor so our recognition is failed. 

Hense √2 is not an rational number so √2 is an irrational number. 


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