Proof:- let sinx=2
(if this is exist then take we value of sinx is 2 otherwise this is proved values of sin x between 1 and -1.)
So using in this pythagorous theorem,
P=2
h=1
b=√(1^2)-(2^2)
b=√1–4
b=√-3(this is not exist so value of sinx or cosx always between -1 and 1) proved