The 2nd and 8 th term of an arithmetic progression are 17 and 1 respectively what is the 14th Term
Solution
Given that
Second(2nd) term of an AP=17
a2 =17
a+d =17 ...............(i)
Eighth term of an AP=1
a8 =1
a+17d=1.............(ii)
from Equation (i) & (ii)
a+d =17 ...............(i)
a+17d=1.............(ii)
After solving Equation (i) & (ii)
a=18
d=-1
the 14th Term (a14)
=a+13d
=18+13(-1)
=18-13
=5
The 7th term of an arithmetic sequence is 34 and 15th term is 66 then what is the common difference
Solution:-
Given that
7th term of an arithmetic sequence is 34
a7 =34
a+6d=34 .................(i)
15th term is 66
a15 =66
a+14d=66 .................(ii)
from Equation (i) & (ii)
a+6d=34 .................(i)
a+14d=66 .................(ii)
After solving Equation (i) & (ii)
a=10
d=4
Hence common Difference=4 Ans...........
