solution:-
let x= a^2/bc+b^2/ca+c^2/ab ...................(1)
and given a+b+c=0
now from(1)
⇒x= a^2/bc+b^2/ca+c^2/ab (Take LCM of ab,bc,ca)
⇒x=(a^3+b^3+c^3)/abc
⇒x=(a^3+b^3+c^3)-3abc+3abc/abc
we know that if a+b+c=0 then a^3+b^3+c^3-3abc=0
so x=(0+3abc)/abc
⇒x=3abc/abc
⇒x=3 ans
also see this video
