if the zeroes of the polynomial x^3-3x2+x+1 are a-b a a+b find a and b

 Solution:- let the given cubic polynomial p(x)=x^3-3x2+x+1 

 and given zero are a-b,a,a+b.

then we know that 

 sum of zeros=-coefficient of x^2/coefficient of X^3

a-b+a+a+b=-(-3)/1

3a=3

a=1

product of Zero=-constant ter/coefficient of x^3

(a-b).a.(a+b)=-1/1

(1-b).1.(1+b)=-1

1^2-b^2=-1

b^2=1+1

b^2= 2

b=+-√2

For Postive value of b= √2

1-√2,1,1+√2.

For Postive value of b= -√2

1+√2,1,1-√2.