The 7th term of an arithmetic sequence is 34 and 15th term is 66 then what is the difference
Solution:-given that 7th term of Ap is 34
Means,
a7=34
a+6d=34 ......... (1)
Again, 15th term of Ap is 66
a15=66
a+14d=66....... (2)
From equation 1 and 2
a+6d=34 ......... (1)
a+14d=66....... (2)
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Finally we get,
-8d=-32
8d=32
d=4
hence common difference is 4.
