find the roots of the equation x^2-3x-m(m+3)=0 where m is a constant
Solution:- given the equation is
x^2-3x-m(m+3)=0
⇒x^2-3x-m^2-3m=0
⇒x^2-m^2-3x-3m=0
⇒(x-m)(x+m)-3(x+m)=0
⇒(x+m)(x-m-3)=0
⇒(x+m)=0 or (x-m-3)=0
⇒x=-m or x=m+3
Hence roots is -m, m+3
find the roots of the equation x^2-3x-m(m+3)=0 where m is a constant
Solution:- given the equation is
x^2-3x-m(m+3)=0
⇒x^2-3x-m^2-3m=0
⇒x^2-m^2-3x-3m=0
⇒(x-m)(x+m)-3(x+m)=0
⇒(x+m)(x-m-3)=0
⇒(x+m)=0 or (x-m-3)=0
⇒x=-m or x=m+3
Hence roots is -m, m+3