if sin theta = root 3/2 then cosec theta + cot theta
Solution:- Given that sinϴ=√3/2
We have to find value of cosecϴ + cotϴ............ (A)
We know that sinϴ=perpendicular(P)/hypotaneous(H)
So, perpendicular(P)=√3
hypotaneous(H)=2
Again we know that by Pythagorean theorem,
Base(b) =√(H^2-p^2)
So, b=2^2-(√3)^2
b=4-3=1
b=1
(A)⇒ cosecϴ + cotϴ=hypotaneous(H)/perpendicular(P)+Base(b)/perpendicular(P),
So, cosecϴ + cotϴ
= 2/√3 -1/√3
=2-1/√3
=1/√3 ans...
