solution:-
calculation of the atomic mass of an element-
Let the atomic mass of the element which is to be determined=M
Density of the element=d gcc^-1
Let the edge of the unit cell=a cm
volume of the unit cell=a^3 cm^3
Density of the unit cell will be the same as the density of the element.
Mass of the unit cell=d×a^3 g
Atomic mass of the element(M)= Mass of the atom × N0
where N0=avogardo's number =6.023 × 10^23
Now the mass of the unit cell=No. of atoms in the unit cell × mass of the each atom
=Z× m
M=(6.023 × 10^23×a^3×d)/Z
Hence Atomic mass M= (N0 ×a^3×d)/Z
where z=4 for fcc
z=2 for bcc
z=1 for simple cubic.
Ans