What is the nature of roots of quadratic equation x^2 -2x- 4=0 ?

 Soln:-Given that the equation x^2 -2x- 4=0 

The standard form of quadratic equation is ax^2+bx+c=0 ,where a≠0 and a,b and c are real are real numbers.

so after comparing  a=1 , b=-2 c=-4

now we know that D=b^2-4ac 

D=(-2)^2 - 4×1×(-4)

D= 4+16=20>0

Here value of D is greater than 0 so nature of of roots is real and Different .

 What is the nature of roots of quadratic equation x2 -2x+ 4 =0?

 Soln:-Given that the equation x^2 -2x+ 4=0 

The standard form of quadratic equation is ax^2+bx+c=0 ,where a≠0 and a,b and c are real are real numbers.

so after comparing  a=1 , b=-2 c=4

now we know that D=b^2-4ac 

D=(-2)^2 - 4×1×4

D= 4-16=-12<0

Here value of D is less than 0 so nature of of roots is not real.

What is the discriminant and nature of roots of x^2+2x+ 4=0?

 Soln:-Given that the equation x^2 +2x+ 4=0 

The standard form of quadratic equation is ax^2+bx+c=0 ,where a≠0 and a,b and c are real numbers.

so after comparing  a=1 , b=2 c=4

now we know that D=b^2-4ac 

D=(2)^2 - 4×1×4

D= 4-16=-12<0

Discriminant=-12

Here value of D is less than 0 so nature of of roots is not real.

 What is the nature of the roots of x^2-4x+4= 0?

What is the nature of roots of quadratic equation 2x² 4x 3 0 *?