A wire is bent to form a square enclosing an of 484 m^2.using the same wire a circle is formed. Find the area of the circle.
Solution: Given a wire is bent to form a square enclosing an 484 m^2 so, we can write
Area of square=484 m^2
Also, a^2=484
⇒a=√(484m^2)
a=22 m
Hence length of side of square=22 m
According to Question, same wire is formed a circle so,
Perimeter of circle=perimeter of square
2πr=4×22 m
⇒2× (22/7)× r=4×22
⇒2× (22/7)×r=4×22
⇒r=(4×22×7)/(2×22)
⇒r=2×7
r=14 m
Hence area of circle=πr^2
=(22/7)×(14)^2
=(22×14×14)/7
=616 m^2
