Bihar board class 10th math exercise 5.3 question 3(ii) in hindi
Ncert class 10th math exercise 5.3 Q3(ii) in hindi
3(ii) a=7 और a13=35 दिया है। d और S13 ज्ञात कीजिए।
हल : दिया गया है कि a=7 और a13=35 है।
चूँकि a13=35
इसीलिए ,a+12d=35
7+12d=35
⇒12d=35-7
⇒12d=28
⇒d=(28/12)
⇒d=(7/3)
अब S13= (13/2)[a+a13]
=(13/2)[7+35]
=(13/2)[42]
=(13×42)/2
= 13×21
= 283
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