class 10th math exercise 5.3 question 3(iii) in hindi
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class 10th math exercise 5.3 question 3(iii) in hindi

 Bihar board class 10th math exercise 5.3 question 3(iii) in hindi

Ncert class 10th math exercise 5.3 Q3(iii) in hindi

 3(iii). एक AP में, a12=37  और d =3 दिया गया है। a और S12 ज्ञात कीजिए।

हल :-  दिया गया है  a12=37 

मतलब , a +11d =37 ....... (i)

और दिया गया है कि d =3 

इसीलिए d का मान समीकरण (i) में रखने पर हम पाते हैं कि 

 a +11×3 =37

a +33=37 

a =37-33 

a=4 

प्रश्नानुसार, चूँकि हम जानते हैं कि  Sn=(n/2)[2a+(n-1)d]

 S12=(12/2)[2×4+(12-1)×3]

 =6[2×4+11×3]

 =6[8+33]

 =6×41

 =246 

Class math exercise 5.3 Q.3(ii) in hindi⇒click here

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