Bihar board class 10th math exercise 5.3 question 3(ix) in hindi
Ncert class 10th math exercise 5.3 Q3(ix) in hindi
10th class math Exercise 5.3(ix) hindi mei
3(ix) a=3, n=8 और S=192 दिया है। d ज्ञात कीजिए।
हल : दिया गया है कि a=3, n=8 और S=192 है।
चूँकि S8=192
इसीलिए सूत्र Sn=(n/2)[2a+(n-1)d] से, हम पाते हैं कि
(8/2)[2×3+(8-1)d]=192
⇒4[6+7d]=192
⇒[6+7d]=(192/4)
⇒6 +7d=48
⇒7d=48-6
⇒7d=42
या d=6
अतः d= 6 है।
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class 10th math exercise 5.3 question 3(x) in hindi- click here
